explain following program

Question

#include<stdio.h>
# define square(x)(x*x)
int main()
{
int x,y=1;
x=square(y+1);
Printf("%d",x);
Return 0;
}

Answer 1

Macro are just replaced by arguments as it is first then evaluated..
So
y =1
x = square(y+1)
=> x = (y+1 * y+1) since #defune squire(x) (x*x)
=>x = 1+1*1+1 =1+1+1 =3
Prints 3

Edit: yes,
Hoping capital X, p are due to autocorrections...

Note : if #defune squire(x) (x)*(x),
then (1+y)*(1+y) = (1+1) * (1+1) = 2*2 =4

Answer 2

Tq u so much.