+ 2
Can you guide me where am i going wrong
This program is to print reverse of string https://code.sololearn.com/cTGwghAJPbzj/?ref=app
9 Respostas
+ 3
#include <stdio.h>
#include<string.h>
int main()
{
int i,j=0,p;
char s[100],rev[100];
printf("enter your string:");
//gets(s); //gets works but use fgets
fgets(s,100,stdin);
p=strlen(s);//s[p] ='\0';
printf("length=%d",p);
for(i=p-1;i>=0;i--) //I = p-1 must
{
//while(j<p-i)
//you don't added braces to include j++ so it's infinite loop, i added, but actually no need of while loop here.. So causing to fail the code actually...
{
rev[j]=s[i];
j++;
}
}
printf("your rev string is:%s",rev);
return 0;
}
+ 1
take the code jayakrishna posted and add rev[p]=0;
to end the string
0
Thanks
0
Okay nils
thanks nils
0
Can you tell me Jayakrishna🇮🇳 why is while loop not working or why while is causing trouble please
0
the while loop would start in the first itaration of your for loop, then execute until j becomes p. after that every iteration of your for loop does nothing because yor while condition is always false. i see what you intended, but you don't need the while loop and its condition because in the last iteration of Jayakrishna's for loop j will be p and execution stops after that.
0
Thanks nil
0
Prashant Pandey
I already added explanation in code as comments...
In your original code, you don't have any braces around while, so only next one statement belong to while so j++ not belong while so condition is true always, makes infinite loop.. Check again that..
In the code above, I put braces, the while condition is j<p-I, only adding one to j condition becoming false.. Only there is only one iteration happening, hence no need of loop.. So I commented. Without or with while is same there...
0
Thanks