Functional Programming

Question

def apply_twice(func, arg):
return func(func(arg))

def add_five(x):
return x + 6

print(apply_twice(add_five, 11))

Why output is 23?
It should be 22.

Answer 1

The control flow is something like this-

1. add_five receives 11 and add_five.
2. It has return statement with branched function call.

func(func(arg)) = func(17) (it adds 6 to 11)
func(17) = 23 (it adds 6 to 17)

Answer 2

Why would you call a function that adds 6 "add_five"? Variable names should help the readers not confuse them 🙃

Answer 3

David Ashton à la SL quiz. :>

Answer 4

Hatsy Rei Hmm Jash's question is the same as https://www.sololearn.com/learn/JUMP_LINK__&&__Python__&&__JUMP_LINK/2459/ first lesson except there add_five() returns x + 5 and the argument is 10 not 11. I couldn't find the quiz (?)

Answer 5

Everyone don't work as per their names.

It's name is add_five but it actually adds 6.😜😀😀

Just like Kushboo naam ki ladki bhi badbu lagti hai 😜😂😂😎