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Hello I'm new in this community just joined didn't know how to ask question but below is my question?

In this two recursive function I'm not able to get how the procedure performing and return the result as 55 in one and 0 in other can someone experienced programmer can explain this two codes working... https://code.sololearn.com/clpNsbAzE2G9/?ref=app https://code.sololearn.com/c1IlhI8EBwv0/?ref=app

20th Sep 2020, 11:01 AM
Sanaya Singhaniya
Sanaya Singhaniya - avatar
3 Respostas
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5 is too big, isn't it? Let's start from 1 :). P2: func2(1) -> 0 + func1(func2(0)) -> 0 + func1(0) //func2(0) returns 0 -> 0 + 0 //func1(0) returns 0 -> 0 So func2(1) == 0 Let's increase the value to 2! func2(2) -> 0 + func1(func2(1)) From the example above, we know func2(1) = 0. -> 0 + func1(0) -> 0 + 0 = 0 So func2(2) is 0 and so on... func2( anyValue ) is 0. P1: let i1 be i in fun1, i2 be i in fun2 fun2(1) -> 0 + fun1(1) //i1 becomes 1 from 0 -> 0 + 1 = 1 //i2 becomes 1 from 0 So fun2(1) = 1 fun2(2) -> 0 + fun1(2)... //i1 becomes 2 from 0 -> 0 + 2 = 2 //i2 becomes 2 from 0 -> 2 + fun1(1) //i1 becomes 3 from 2 -> 2 + 3 = 5 //i2 becomes 5 from 2 So fun2(2) = 5 From that we know fun2(n) is fun1(n) + fun1(n-1) + ... + fun(1) where fun1(n) is i1 + n + n-1 + ... + 1 fun2(5) = fun1(5) + fun1(4) + fun1(3) + fun(2) + fun(1) = 5 +5+4 //i1 is 5 +5+4+3 //i1 is 5+4 +5+4+3+2 //i1 is 5+4+3 +5+4+3+2+1 //i1 is 5+4+3+2 = 25 + 16 + 9 + 4 + 1 = 55
20th Sep 2020, 12:13 PM
你知道規則,我也是
你知道規則,我也是 - avatar
+ 1
I'm not all that with recursions, I'll just share you the tips for Q&A forum, and leave the answer for a more knowledgeable friend. Oh, and welcome to SoloLearn ... almost forgot. https://www.sololearn.com/Discuss/1316935/?ref=app https://www.sololearn.com/Discuss/333866/?ref=app
20th Sep 2020, 11:10 AM
Ipang
+ 1
Thanks for the explanation CarrieForle. Thanks for guideline links Ipang
20th Sep 2020, 2:34 PM
Sanaya Singhaniya
Sanaya Singhaniya - avatar