[Solved]Why is it giving me two different addresses??

Question

https://code.sololearn.com/cWvem85YcY1I/?ref=app

Thanks everyone 😊

Answer 1

*p returns the value at address pointed by pointer variable p.
p returns the address pointed by p.
&p returns the address of p itself.

Answer 2

https://stackoverflow.com/questions/37366625/what-is-the-difference-between-p-and-p#:~:text=It%20gives%20address%20of%20pointer%20p%20.&text=With%20the%20%22%25p%22%20format,**%20)%20and%20print%20that%20pointer.

Answer 3

#include <iostream>
using namespace std;

int main()
{
int *p = new int;
*p = 5;
cout<<*p<<endl; //--> that's mean value of variable
cout<<p<<endl; //--> that's mean address of variable, whose pointing pointer
cout<<&p; //--> that's mean address of pointers p
}
//So it gives you two different address, hope you understood.