Elif Statements / Python

Question

https://www.sololearn.com/coach/126?ref=app

Write a program that will be used in a robot that categorizes items by their color.

Each color corresponds to a box with a specific number.

For simplicity, our program will handle 3 colors:

red goes to box #1
green goes to box #2
black goes to box #3

Your program needs to take a color as input and output the corresponding box number.

Sample Input
green

Sample Output
2

Answer 1

Because you are doing it wrong ,why are you taking color as input when you are not going to use it anywhere?

and

(if red
elif green
elif black),

all results in true ,only the first condition will be checked resulting in output as always 1 according to your solution

Program is asking to check if color is green than output 2 ,if red output 1 and if black output 3

if color=="red":
print(1)
elif color=="green":
print(2)
elif color=="black":
print(3)

Answer 2

Try writing:
if color=="Red":
print(1)
elif color=="Green" :
print(2)
And the same for black.

As the variable color is the input and it should be Red/Green/Black, you have to write: if color=="Red/Green/Black".

Answer 3

color = input()

if color == "red":
print(1)
elif color == "green":
print(2)

...I'm sure you can fill the rest to account for black.

Answer 4

Abhay
Excellent answer.

Answer 5

Rik Wittkopp ty!

Answer 6

Zone oh ok👍

Answer 7

a = 'red'
b = 'green'
c = 'black'
color = input()
if color == a:
print('1')
elif color == b:
print('2')
elif color == c:
print('3')

try this, it is working

Answer 8

color = input()
if color=="red":
print ("1")
elif color=="green":
print ("2")
else:
print("3")

Answer 9

color=input('Enter the color: ')
color1='red'
color2='green'
color3='black'
if(color==color1):
print('Box 1')
elif(color==color2):
print('Box 2')
elif(color==color3):
print('Box 3')
else:
print('Theres no such box corresponding to given color')

Answer 10

I tried

color = input()
# your code goes here

red = 1
green = 2
black = 3

if red:
print(1)
elif green:
print(2)
elif black:
print(3)

And it comes out wrong...🤔

Answer 11

Abhay i was taking color as input because that's what the challenge was telling me to do. Your answer works. I had tried yours before but didn't put the colors in string quotes. Thanks !

Answer 12

Assigning makes things easy

a = input()

if a=="red":
print(1)
elif a=="green":
print(2)
elif a=="black":
print(3)

Answer 13

I tried the below and was incorrect..
if color == red:
print("1")
elif color == green:
print("2")
elif color == black:
print("3")

I can see the difference here...
if color=="red":
print(1)
elif color=="green":
print(2)
elif color=="black":
print(3)
But I can't understand the difference haha.. any tips will be appreciated!!

Answer 14

Riley
Your first code outputs type string.

Your 2nd code outputs type integer.

A string character is similar to text, letters that form a message.

An integer is a number which may be used to resolve math problems.

Strange as it may seem, think of "2" as the letter 2

Think of 2 as the number 2

PS: This query should have been in a separate post

Answer 15

//your code goes here
Scanner sc = new Scanner(System.in);
String color = sc.nextLine();

switch(color){
case "red":
System.out.println(1);
break;

case "green":
System.out.println(2);
break;

case "black":
System.out.println(3);
}

Answer 16

Organized Robot🤖
You are developing a program that will be used in a robot that categorizes items by their color.

Each color corresponds to a box with a specific number.

For simplicity, our program will handle 3 colors:

🔴 red goes to box #1

🟢 green goes to box #2

⚫ black goes to box #3

Your program needs to take color as input and output the corresponding box in the given format.

In the case of an unsupported colors, the program should output unknown.

Input Example⬅️: green

Output Example➡️: box #2