int overrun issue

Question

Hello

I have a question.
int has a range from -2 to the power of 32 to 2 to the power of 32 -1.
If I now assign a int variable to 3 * 1 * 10 to the power of 9, System.out.println will give me an overrun.
Now the Question is . What number do i get? does it end with 5 or 6?
With the IDE i get a 6 but when i count it with Geogebra i get 5.

thanks for your help

Answer 1

Sanoj i don't get what do you mean by 5 or 6..?

Integer range in java is -2147483648 to 2147483647.
If you exceed the value of max value then you will get the number count from minimum value..
Add an example for your description...

Answer 2

Int has a range -2 in power of 31 to 2 in power of 31 - 1, btw. 2 in power of 32 is a total number of values.

Answer 3

@ Jayakrishna
with 5 or 6 i mean the last digit of the result when you calculate
3*1 *10^9. What result do you get?
-1294967295 or -1294967296

Answer 4

6 in code playground
https://code.sololearn.com/cHIrcLyoyF6I/?ref=app

Answer 5

With 3*10^8 only you get correct result, and 3*10^9 you are getting overrun..
6 getting but 5 or 6 both overrun values.. What is the difference..