I just wrote a code for multiplication for input of any number till the 20 multiples .

Question

// the multiplication table of any input number till its 20 multiples

#include <iostream>
using namespace std;

int main()
{
int num;
cout<<"The Multiplication table of ";
cin>>num;
int numstatic=num;
int multiple=0;
cout<<num<<" till it 20 Multiples is \n";

while (num < numstatic*20+1) {
multiple ++;
cout<<numstatic<<"×"<<multiple<<"="<< num << endl;
num = num + numstatic;
}

return 0;
}

Everything works fine when I remove cin and put some value of num but when I make num as input by putting cin as in the code it gives out of some number like 32627

Answer 1

Aquib Javid Mir oh ok I didn't understood the question really ,

Answer 2

The code that you have in your description works fine for me , not sure what you are taking about

Answer 3

Abhay actually while after I run the code I get output as
32627×1
32627×2.....
However ,shouldn't I get the output as
0×1
0×2.....
Because there is not input till now

Answer 4

That's a garbage value.

That you will get, if you not assigning value before using it..

Answer 5

Jayakrishna🇮🇳 thanks

Answer 6

You're welcome..