[Error] 'size' undeclared here (not in a function)

Question

I wrote a function called magic square and Functions should not have pointers implementations. I have stuck with the line int sq[size][size], int size and this prints out the error message. My code is below:
#include<stdio.h>
int count=1;
int print(int sq[size][size], int size){
int i,j;
for(i=0;i<size;i++){
for(j=0;j<size;j++)
printf("%5d",sq[i][j]);
printf("\n");
}
}
int init(int sq[size][size], int size){
int i,j;
for(i=0;i<size;i++)
for(j=0;j<size;j++)
sq[i][j]=0;
}
int Algorithm(int sq[size][size],int size,int i, int j, int count){
int row,column;
if(count>=size*size){
sq[i][j]=count;
}
else {
sq[i][j]=count;
row=(i-1<0)?(size-1):i-1;
column=(j-1<0)?(size-1):(j-1);
if(sq[row][column]){
i=(++i)%size;
}
else{
i=row;
j=(j-1<0)?(size-1):--j;
}
Algorithm(sq,size,i,j,count+1);
}
}
int main(void){
int i,j,row,col;
int size;
//detect the size
printf("input the size of the square: ");
scanf("%d",&size);
while((!(size%2))||size>9||size<5){
printf("This is not a available number, plz try again:");
scanf("%d",&size);
}
int sq[size][size];
for(j=0;j<size;j++){
sq[size][size]=sq[size][j];
}
//initialize the data
init(sq,size);
i=0;
j=(size-1)/2;
Algorithm(sq,size,i,j,count);
printf("magic square of size %d : \n\n",size);
print(sq,size);
printf("\n\n");
}
Can someone help me to fix this without using the pointer implementation. Thanks!

Answer 1

You can eliminate the error by moving the size parameter to the left of the array parameter so that size is declared before it is used by the variable-length array declaration. Be certain to update all references that call the function, too.

Here I made the changes, and it started working. Other errors surfaced after that.
https://code.sololearn.com/csxnBy7UaGjL/?ref=app

Answer 2

Thank you very much!!