Why is the output generated here - 1

Question

https://code.sololearn.com/czUCgLI29jTY/?ref=app

Answer 1

When you pass 4-1

The program takes it as this:

4-1 * 4-1

The above expression results in -1, because of bodmas.

4-(1*4)-1
4- 4 -1

in bodmas multiplication is done first compared to subtraction.

Hope u get the idea, Suhani Goyal

Answer 2

Your code will solve look like this
In macro u defined
#define square(x) x*x

printf("%d",square(4-1));
square(4-1) you defined x*x
So
4-1*4-1
Here multiplication have highest precedence so 4-4-1=-1

but if u will write like this
#define square(x) (x)*(x)
noticed here i added bracket so bracket have highest precedence
So it will calculate like this
(4-1)*(4-1)
So in this case
(3)*(3)=9
output will be 9

.............. Thankyou .............

Answer 3

Aditya rout she has doubt's that's why she asked . So don't post unnecessary comments in others post.

Answer 4

Thanks for pointing it out. ♨️♨️

I didnt remember this.

Answer 5

You should use parenthesis to give priority to the expression like this square((4-1)). What will it do for you, it will simply give the value 3*3 instead of 4-1 *4-1 which is -1.

If you want to discuss at a very high level checkout my profile

Answer 6

But square of 3 is 9, why is the answer - 1

Answer 7

#include <stdio.h>
#define square(x) x*x
int main() {
printf("%d",square((4-1));//brackets
return 0;
}
you forgot the math rules?