Full Question is in Description

Question

Suppose here is class of 10 students who have CGPA between 0-10.The university has
decided to give the grace for those students those who bave the CGPA between 4.5 to 4.9 t0
make it 5. Identify the students those have CGPA after adding the grace marks. Suppose
students have its Roll_no &CGPA. Add the grace CGPA to the obtained CGPA of student
by adding grace of5 marks iste the students through array.
Input
The input should contains a roll_oaed CGPA of the students.

Answer 1

Your program have not any Compile time errors. Try to run again

#include <iostream>
using namespace std;
double CgpaCalc(double marks[], int n){
double grade[n];
double cgpa, sum = 0;
for(int i = 0; i < n; i++)
{

grade[i] = (marks[i] / 10);}
for(int i = 0; i < n; i++)

{
sum += grade[i];
}
cgpa = sum / n;
return cgpa;
}

// Driver code

int main()
{

int n = 5;

double marks[] = { 90, 80, 70, 80, 90 };
double cgpa = CgpaCalc(marks, n);
cout << "CGPA = ";
printf("%.1f\n", cgpa);
cout << "CGPA Percentage = ";
printf("%.2f", cgpa * 9.5);
return 0;
}

Answer 2

Ok share your attempt

Answer 3

i unable to solve this problem

Answer 4

Try again and again...this is an easy one .... You can do it ..

Answer 5

double CgpaCalc(double marks[], int n)
{

// Variable to store the grades in

// every subject

double grade[n];

// Variables to store CGPA and the

// sum of all the grades

double cgpa, sum = 0;

// Computing the grades

for(int i = 0; i < n; i++)

{

grade[i] = (marks[i] / 10);

}

// Computing the sum of grades

for(int i = 0; i < n; i++)

{

sum += grade[i];

}

// Computing the CGPA

cgpa = sum / n;

return cgpa;
}

// Driver code

int main()
{

int n = 5;

double marks[] = { 90, 80, 70, 80, 90 };

double cgpa = CgpaCalc(marks, n);

cout << "CGPA = ";

printf("%.1f\n", cgpa);

cout << "CGPA Percentage = ";

printf("%.2f", cgpa * 9.5);
}

but it is showing wrong