List output.

Question

Hi guys,

In the following code, the program outputs the list like this [1, 3, 5, 7].

Why did remove(i) method remove 0,2,4,6 ?

Could you have an idea?

Thanks!

https://code.sololearn.com/cOoqj7PySBij/?ref=app

Answer 1

</€N!GM@>🏴‍☠️ , remove method takes index and removes array element at that index. Your code runs like this:

Initial Array: [0,1,2,3,4,5,6,7,8]

During 1st loop,i = 0 and element at ith position is removed (0)
Array: [1,2,3,4,5,6,7,8]

During 2nd loop,i = 1 and element at ith position is removed (2)
Array: [1,3,4,5,6,7,8]

During 3rd loop,i = 2 and element at ith position is removed (4)
Array: [1,3,5,6,7,8]

This continues and you get your final answer as you told [1, 3, 5, 7].

Answer 2

Lets take a look at second loop)
First itterate removes entry №0 it is 0
Second itterate removes entry №1 it is 2 (because now it contents only [1,2,3,4,5,6]
Third removes entry №3 it 4
Fourth removes №4 it is remaining 6

Answer 3

If you want to remove each entry try second loop as
For i in len(myList):

Answer 4

I got it guys 👍🏻

Alex Vernee
Bhavya Ruparelia

Thank you so much!

Answer 5

</€N!GM@>🏴‍☠️ , if you print array directly then it will be printed as you have told. To print only elements without [], you have to use loop or you can write:
print(" ".join(array_name))
Here join function converts whole array in single line string seperated with space.

Answer 6

Bhavya Ruparelia

I’ve updated my question.

Thanks for your answer.