I'm lost on how the out put doesn't include match 3 yet "g" is part of [a-z]

Question

import re
pattern=r"g"
if re.match(pattern,"gggg")
print("match1")
if re.match(pattern,"g")
print("match2")
if re.match(pattern,[a-z])
print("match3")

Answer 1

I am not very good with this topic.
This is just an example.

import re
pattern = r"[a-z]"
if re.search(pattern,"g"):
print("yes")

Answer 2

To explain further what Benjamin Jürgens has said, the format for re.match (and re.search) methods is re.match(regex_pattern, string). So

re.match(“[a-z]”, “g”) will return True, but
re.match(“g”, “[a-z]”) will return False.

The second one is looking for the char “g” at the start of the string “[a-z]”, which is clearly not there.

Answer 3

"g" is not in "[a-z]"
But "g" is in "abcdefgh..."
You have to write out the alphabet, you can use regex syntax only for pattern

Answer 4

It is clearly mentioned in the course.

"the re.match function can be used to determine whether it matches at the beginning of a string."

Answer 5

Thank you so much

Answer 6

Ohhhhh...so in a code like that what would I use to prove that g is in [a-z]