how to solve this problem using itertools.combination() ?

Question

lst= [ ]

I want to make a list of numbers from 1111 to 9999 (4 digit ) but I don't want to print the numbers which contain 0 and repeated numbers...

like this numbers should be excluded :
1302 #contain zero
5830 #contain zero
1103 #repeated 1
1145
5399 #repeated 9
8555 #repeated 5
2222 #repeated 2

like this in list I don't want a number which contain repeated number..
how to do that?

MY ATTEMPT:
To be honest I am unable to understand the itertools.combination() from doc.python.org

https://code.sololearn.com/chNcQ21GZ4h0/?ref=app

Answer 1

https://code.sololearn.com/ca621DaBw4w9/?ref=app

Answer 2

Ratnapal Shende , the code you posted is not complete and so not really showing a useful try. But as Julia Shabanova has allready presented a ready-to-use code (which is also my preferred version (except that it produces strings instead of integers), but just giving this code does not really help develloping people in coding ability). it's up to you whether you did a try and learn something or if you decide to copy paste. Anyway good luck!

Answer 3

Ratnapal Shende , please show us your attempt first. Thanks!

You can use itertools.permutations(), not combinations(). it starts with:
(I assumed that repeated digits are 1125 as well as 1231.)

1234
1235
1236
1237
1238
...

Answer 4

Lothar edited sir

Answer 5

Lothar sir I am really interested in learning. I searched YouTube videos for it but not found any video which tells about my problem..
I tried a lot sir and finally I asked here..
I didn't copy paste sir.
learned from Julia Shabanova code.
his code produces strings right not integers so can i use int() to convert strings into integers ? or is their any method avaliable already in itertools ?