0

Why the output is coming as 17?

public class Program { public static void main(String[] args) { int result=0; for (int i=0;i<5;i++){ if (i==3) { result +=10; }else { result +=i; } } System.out.println(result); } }

15th Mar 2017, 9:58 AM
Gopi Mehta
Gopi Mehta - avatar
5 Respostas
+ 9
Like my other answer (same question): Normally it loops through and adds i to result, except when i is 3, in which case it adds 10. Here it is: Loop # i val. result val. 1. 0. 0 2. 1. 1 (0+1) 3. 2. 3 (1+2) 4. 3. 13 (3+10 because i is 3) 5. 4. 17 (13+4) 6. 5. i is not < 5 so the loop body is not executed. It exits the loop and prints result, which is 17. I hope this helps.
15th Mar 2017, 10:07 AM
J.G.
J.G. - avatar
+ 1
Because in the for loop, if I is equal to 3 then add 10 to the variable result, else add I to the variable result. So, 0 + 1 + 2 + 10 + 4 = 17
15th Mar 2017, 10:01 AM
Mohamad Abdelhafiz
Mohamad Abdelhafiz - avatar
0
@Mohamad Abdelhafiz Sorry actual source code was this and the output is 17 can you explain this?
15th Mar 2017, 10:06 AM
Gopi Mehta
Gopi Mehta - avatar
0
In starting result = 0, according to if condition result += i, means you add i in result where i=3 therefore result += 3 , result = 3.
15th Mar 2017, 10:06 AM
Mohit Kumar
Mohit Kumar - avatar
0
@Mohit Kumar the question is modified pls check.
15th Mar 2017, 10:07 AM
Gopi Mehta
Gopi Mehta - avatar