Find the missing number in an integer array of 1 to 10. For eg :- I/p - 1,2,4,5,6,8,9,10 o/p- 3 and 7

Question

Use array in java

Answer 1

Your attempt first.. Pls try and share you attempt....

Answer 2

I tried for one missing element , that too an error is occurring
import java.util.*;
public class Program
{
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
System.out.println("enter the limit");
int n=sc.nextInt();
int a[]=new int[n];
int sum=0;
for(int i=0;i<n;i++)
{
a[i]=sc.nextInt();
System.out.print(a[i]+",");
sum=sum+a[i];
} System.out.println();
int totalsum=(n*(n+1))/2;
int missing=totalsum-sum;
System.out.println(missing);
}
}

Answer 3

I don't find any error in Program. But
You are taking array size, then elements. Finding sum of array elements and subtracting it from (sum of n sequence number).. This approach i don't find 'how it find missing elements'?
According to your question, in a simple way you can do like : you need find 1 to 10 numbers so no need to take input of array size, declare array of size 10. And next just take inputs, if input is in range 1 to 10 then set array[input-1] = 1 and next with a loop you can find missing elements where array[i] ==0. Output i+1.

You can also do with taking inputs and next with 2 loop, checking if array contains 1 to 10 are not.. There are alternatives but the those may take more loops or comparisons... Hoping it helps.. Reply if you have any difficulty in getting it solved..