The __init__ magic method arguments

Question

Hello everyone, I'm learning Python and currently trying to embrace the OOP section.

Can someone please explain how it affects my created class, if I don't state the arguments I use in the brackets in the headline right after "__init__"?

Here's some example.
https://code.sololearn.com/c65cXcwCAGgS/?ref=app

Answer 1

That means you are creating three variables, right when the class is created

Answer 2

those are not arguments

Answer 3

__init__ is a constructor for a class, meaning that whenever an instance of that class is created, that function is called right away

Answer 4

Every __init__ definition must have “self” as an argument or it won’t be associated with the class

Answer 5

Okay, but what about the line 3 in the example code: def __init__(self):

I don't put any arguments in the brackets except for 'self'. Yet I can still use them as usual. What difference it makes when I do state them and when I do not?

Except for 'self', I have there '_desc', 'class_name', 'health'.

Answer 6

So this also means that I set new values for them each time I create new object. Thank you man! I think I understood it now.

Answer 7

Yup!