Java Loan calculator case 5

Question

import java.util.Scanner;

public class Program
{
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int amount = scanner.nextInt();
//loan amt left
int paid;//amount paying

double accuamt = amount;//mirror input
double accupaid;//amount paying decimals
for(int x=1; x<=6; x++)
{

accupaid = accuamt /10;//finding 10%
paid = amount/10; //finding10%to1decimal
amount = amount - paid;
accuamt =accuamt -accupaid;//reducing total amount
if((accuamt % amount)>0){
amount --;}//forcing round down

if(x==6)
System.out.println(amount);//printing values

}
}
}

If I don't force a round down, I always have answer +1. This code works for cases 1-4 :c pls halp. I'm SO CURIOUS. Also I read that Java rounds down integer division so this is confusing me. And we havent learnt abt the rounding function so I tried not to use it, unlike some of the other solutions

Answer 1

Jeroen Ow

Well it's a complex code. You can do in just 4-5 step

double amount = scanner.nextInt();

for(int x = 1; x <= 6; x++)
amount = amount - Math.ceil(amount / 10);

System.out.println((int) amount);

Answer 2

Jeroen Ow Yes but we have to use it to get actual result.

Answer 3

Jeroen Ow Congratulations

Answer 4

I Am Groot ! Oh yes, thank you. I did get the 50exp :D

Answer 5

I Am Groot ! Well the question didn't say anything about math.ceil or math.floor. :c

Answer 6

I Am Groot ! can you please tell me what is Math.ceil?

Answer 7

Use 90% for 6 months to find the balance.
4 lines of code added.

https://code.sololearn.com/cp6GXE4Rc84v/?ref=app

If you are paying 10% every month, one way is to find the 10% and then use your total minus the 10% paid to get the balance.

The other way, is to find the 90% so you don't have to minus.

If you have 100 and you paid 10%,
Method 1: 100 - (100 * 10%) = 90
Method 2: 100 * 90% = 90

The "i=0" is used for looping. It will loop from 0 until 5 (< 6), which is 6 times.

Finally prints out amount.