Currency converter, can you point out errors?

Question

function main() {
var amount = parseFloat(readLine(), 10);
var rate = parseFloat(readLine(), 10);
console.log(convert(amount, rate));
}
function convert(a;b){
return = a*b;
console.log(convert (100;1.1))
}

Answer 1

Alim Niyazov , first you don't need to print with specific values =>console.log(convert(100, 1.1). Replace semicolons with commas between the function parameters and arguments. You can't say return = a * b. Instead write return a * b
try this way :
function main() {
var amount = parseFloat(readLine(), 10);
var rate = parseFloat(readLine(), 10);
console.log(convert(amount, rate));
}
function convert(a,b){
return a*b;
}

Answer 2

Rewrite the convert function like :
function convert(a,b)
{
return a*b ;
}

Answer 3

thank you very much for making such stupid mistakes