A palindromic number is a number (such as 626) that remains the same when its digits are reversed. Write a function that returns

Question

#include <iostream>
using namespace std;

bool isPalindrome(int x) {
//complete the function

}

int main() {
int n;
cin >>n;

if(isPalindrome(n)) {
cout <<n<<" is a palindrome";
}
else {
cout << n<<" is NOT a palindrome";
}
return 0;
}

What I have written wrong in this code i am trying this from 10 minutes
but it gives me null please type the code in answer

Answer 1

You have to code this function for this to work.

bool isPalindrome(int x) {
//complete the function

}

Answer 2

#include <iostream>
using namespace std;

int main()
{
int n, num, digit, rev = 0;

cin >> num;

n = num;

do
{
digit = num % 10;
rev = (rev * 10) + digit;
num = num / 10;
} while (num != 0);

if (n == rev)
cout <<n<<" is a palindrome";
else
cout <<n<<" is NOT a palindrome";
return 0;
}
I think it will help you :)

Answer 3

#include <iostream>
using namespace std;

int revdigit(int y){
int rem, rev=0;
while(y>0){
rem = y%10;
rev = rev*10+rem;
y = y/10;
}return rev;

}

bool isPalindrome(int x) {
//complete the function

if(x==revdigit(x)){
return true;
}
else{
return false;
}

}

int main() {
int n;
cin >>n;

if(isPalindrome(n)) {
cout <<n<<" is a palindrome";
}
else {
cout << n<<" is NOT a palindrome";
}
return 0;
}

Answer 4

#include <iostream>
using namespace std;

int main()
{
int n, num, digit, rev = 0;

cin >> num;

n = num;

do
{
digit = num % 10;
rev = (rev * 10) + digit;
num = num / 10;
} while (num != 0);

if (n == rev)
cout <<n<<" is a palindrome";
else
cout <<n<<" is NOT a palindrome";
return 0;
}

Answer 5

You need to complete the bool function first "//complete the function".

Answer 6

#include <iostream>
using namespace std;

bool isPalindrome(int x) {
//complete the function
int temp = x;
int lastDigit, reverse = 0;
while (x>0)
{
lastDigit = x % 10;
reverse = (reverse*10) + lastDigit;
x/=10;
}
if (temp == reverse)
{
return true;
}
else
{
return false;
}
}

int main() {
int n;
cin >>n;

if(isPalindrome(n)) {
cout << n <<" is a palindrome";
}
else {
cout << n <<" is NOT a palindrome";
}
return 0;
}

Answer 7

idk semza code is working perfectly why people didn't like