Why all if statements go true ?

Question

//simple calculator
#include <iostream>
using namespace std;
int main() {int i,a;float s=0;
char op,o;
cout<<"Enter the number of operations :";
cin>>i;//where i is the number of operations
cal :cout<<"Enter the number(a) :";
cin>>a;
cout<<"Enter +, -, × or ÷ : ";
cin>>op;//where op is the sign of operator
o=op;
if (op ='+') cout<<"+"<<endl;
if (o ='÷') cout<<"÷"<<endl;
if (op ='-') cout<<"-"<<endl;
if (op ='×') cout<<"×"<<endl;
i=i-1;
if (i != 0) goto cal;
cout<<"The result is "<<s;
return 0;
}

Inputs :
1
1
-
Output:
+
÷
-
×
The result is 0

Answer 1

You should use "==" operator
Instead of "="

Answer 2

You should use a comparison operator "Equal to"(==)
Best of Luck!

//simple calculator
#include <iostream>
using namespace std;
int main() {
float i=0, a=0;
float s=0;
char op;

cout<<"Enter the 1st number : ";// number 1(i)
cin>>i;
cal :cout<<"Enter the 2nd number : ";// number 2(a)
cin>>a;
cout<<" Addition(+) \n Subtraction(-) \n Division(/) \n Multiplication(*) \n";
cout<<"Enter what do you want : ";
cin>>op;//where op is the sign of operator

if (op =='+'){
s=i+a;
cout<<s<<endl;
}
if (op =='/'){
s=i/a;
cout<<s<<endl;
}
if (op =='-'){
s=i-a;
cout<<s<<endl;
}
if (op =='*'){
s=i*a;
cout<<s<<endl;
}
return 0;
}