arrays in a 'for' loop

Question

Hi guys!
So I'm stuck again on a challenge:

You are given an array of doubles of items in a store that have different prices (see template).
Write a program that takes the "percent off" discount as input and outputs discounted item prices on one line in the same sequence you are given, separated by a space (" ")

here is my code, which obviously only gives me the calculation for the last price, because I can't figure out the right way to output results in requested order

#include <iostream>
using namespace std;

int main() {
double items[] = {500, 12.4, 94, 45, 3, 81, 1000.9, 85, 90, 1, 35};
int discount;
double finPrice;

cin>>discount;
for (int x=0; x<11; x++) {
finPrice=items[x]-(items[x]*discount)/100;
}
cout << finPrice << endl;
return 0;
}

https://www.sololearn.com/learning/1051/1628/2852/2

Thanks in advance!

Answer 1

#include <iostream>
using namespace std;
int main() {
double items[] = {500, 12.4, 94, 45, 3, 81, 1000.9, 85, 90, 1, 35};
int discount;
double finPrice;
cin>>discount;
for (int x=0; x<11; x++) {
finPrice=items[x]-(items[x]*discount)/100;
cout << finPrice << " ";
}
return 0;
}

Answer 2

Congrats and happy coding furthermore.

Answer 3

Hints:

double finPrice[11];

Make the "finPrice" an array so it will store each item's discounted price.

Then use the "for loop" to iterate each item and insert each discounted prices of items to "finPrice" array.

Finally, use "for loop" to iterate each discounted items from "finPrice" array then print each followed by spaces.

The code is up to you. If you're still stuck, please feel free to ask. Thanks and Good luck!

Answer 4

Valerie S
Typo Error in mine

It is "finPrice" array not "discount".
Sorry, a mistake.

Answer 5

oh, that makes more sense, thanks!

Answer 6

omg, somehow my version of the same code as JaScript suggested is not working at all, I've checked everything three times >.<

Update: it works, i was just being stupid

Answer 7

thank you sm!
gonna try to wrap my head around this for now

Answer 8

>.<

Answer 9

#include <iostream>
using namespace std;

int main() {
double items[] = {500, 12.4, 94, 45, 3, 81, 1000.9, 85, 90, 1, 35};

//your code goes here
float discount;
float discounted;
cin >> discount;

for (int x = 0; x < 11; x++) {
discounted = items[x] - items[x] * discount / 100;
cout << discounted << " ";
}

return 0;
}

Answer 10

#include <iostream>
using namespace std;

int main() {
double items[] = {500, 12.4, 94, 45, 3, 81, 1000.9, 85, 90, 1, 35};
double num ;
cin>>num;
//your code goes here
for(int i=0;i<11;i++)
cout<<items[i]-items[i]*num/100<<" ";

return 0;
}

Answer 11

A way easier solution is this.

#include <iostream>
using namespace std;

int main() {
double items[] = {500, 12.4, 94, 45, 3, 81, 1000.9, 85, 90, 1, 35};

//your code goes here
int p;
int x;
cin>>p;
//where p is the input discount
do{
cout<<items[x]-(items[x]*p)/100<<" "<<endl;
//note: the <<endl can be removed if necessary.
x++;
} while (x<11);

return 0;
}

Answer 12

I dont get it ..why we are not using x<=11 instead of x<11...and why x<=11 s showing error?

Answer 13

Can anyone explain that if total is 1947.3 .. then discount of 30% should be 1363.11 but it shows 24.5..any idea why?

Answer 14

When postings please do well to post every last info 🙏🙏

Answer 15

#include <iostream>
using namespace std;

int main() {
double items[] = {500, 12.4, 94, 45, 3, 81, 1000.9, 85, 90, 1, 35};

//your code goes here
int a;
cin>>a;
double discounted;
for(int i=0;i<11;i++)
{
discounted=items[i]-a*items[i]/100;
cout<<discounted<<" ";
}

return 0;
}

Explanation:

I use this formula because it's easy to understand

items[i]-a*items[i]/100

Same as>> nums - perc%

Let say:

The value of nums is 500
And the sample percentage input is 25
To get the percentage we need to multiply 500 by 25 and divide it into 100 >>(500*25/100) the answer is 125 then reduce 500 by 125

500-125=375

Done!☑️

Answer 16

#include <iostream>
using namespace std;

int main() {
double items[] = {500, 12.4, 94, 45, 3, 81, 1000.9, 85, 90, 1, 35};
double percentageOff;
cin>>percentageOff;
percentageOff = percentageOff/100;
//your code goes here
for(int x = 0; x < 11; x++){
cout<<items[x]*(1-percentageOff)<<" ";
}
return 0;
}

Answer 17

#include <iostream>
using namespace std;
int main() {
double items[] = {500, 12.4, 94, 45, 3, 81, 1000.9, 85, 90, 1, 35};
int discount;
double finPrice;
cin>>discount;
for (int x=0; x<11; x++) {
finPrice=items[x]-(items[x]*discount)/100;
cout << finPrice << " ";
}
return 0;
}

Good Luck

Answer 18

#include <iostream>

using namespace std;

int main() {
double items[] = {500, 12.4, 94, 45, 3, 81, 1000.9, 85, 90, 1, 35};

//your code goes here
double discount;
cin>> discount;

double equ;

for(int i=0; i<=10;i++ )
{
equ=items[i] - discount*(items[i]/100);

cout<<equ<<" ";
}

return 0;
}