Why short double doesn't work?

Question

// находит сумму всех положительных чисел массива

#include <iostream>
#include <cmath>
using namespace std;

int main() {
int n = 6, i=0;
short double sum =0; // the compiler swears at this line
double arr[n] = {2.3, -4, 6, 7, 1.23, 14};

// перебирает элементы массива
while (i < n){
if (arr[i] > 0) sum+=arr[i];
i++;
}
cout <<"Sum of positive numbers = "<< sum << endl;
return 0;
}

Answer 1

`short` is one of the type modifiers in C/C++ that changes the related type storage space & data range. As I understand it, `short` is only applicable to integer type (`double` is floating point type).

For more info about modifiers, please refer the following link

https://www.techcrashcourse.com/2015/11/modifiers-in-c-constants-data-types-c.html

Answer 2

There is no `short double` type as I understand it. There's `long double` however, maybe you meant to use that one instead.

Answer 3

Really?! Ohh, thank you very much, and with what data types can you use "short"?

Answer 4

I am very grateful to you!!!