Why won’t the code work when 2000 plugged in help please it’s for the leap year checker

Question

year = int(input())
if (year % 4):
if (year % 100):
if(year % 400):
print('leap year')
else:
print("Leap year")
else:
print('Not a leap year')

Answer 1

It is because when you divide 2000 by 4 the remender will be 0 , and 0 is considered as False , if you want that condition be True then you can apply this if (year % 4 == 0) or if (not year % 4) , it will give you True in leap year! Because if 0 reminder will come then 0==0 will be True and not 0 will be True

https://code.sololearn.com/cssJxMhziikv/?ref=app

See this code , All the best!

Answer 2

if year%400==0 or (year%4==0 and year%100!=0) : #leap year

Answer 3

thank you

Answer 4

sorry it has me set it up so the iser can plug a number in and find out if its leap year or not

Answer 5

so how do infix it so it will work with any year

Answer 6

Just write, int(input()) where I have written 2000