letter frequency on python data structures

Question

Guys please can you help me on the first project of python data structures im stuck please thank you on the letter frequency

Answer 1

Hope you're asking about this one :)
stri=input()
L= input()
print(int(stri.count(L)/len(stri)*100))

Answer 2

LETTER FREQUENCY
word=input()
letter=input()
n=len(word)
per=((word.count(letter)/n)*100)
print(int(per))

Answer 3

Please share your attempt for your project as well as add description details to your question.

Answer 4

txt = input()
lter = input()

co = 0
for i in txt:
if i == lter:
co +=1

print(int(co/len(txt)*100))

Answer 5

Thank you very much, My last line was wrong

Answer 6

Thanks a lot!

Answer 7

letter frequency:

text = input()
letter = input()
counter = text.count(letter)
frequency = int ((counter/len(text)) * 100)
print(frequency)

Answer 8

¿¿¿¿Just give a hint or something????

Answer 9

text = input()
letter = input()
x = text.count(letter)
y = len(text)
percentage = (x*100)/y
print(int(percentage))

Answer 10

Here is my solution (hope it helps)
text=input()
letter=input()
count=0
frequency=0
for c in text:
if c==letter:
count+=1
n=len(text)
frequency=(count/n)*100
print(int(frequency))

Answer 11

#simple solution
w = input()
l =input()
n=len(w)
p =((w.count(l)/n)*100)
print(int(p))

Answer 12

first = input()
second = input()
suum = first.count(second)
div = len(first)
total = (suum / div) * 100
print(int(total))

Answer 13

dat = input()
x = input()
vs = dat.count(x)
res =int((vs/len(dat))*100)
print(res)

Answer 14

More readable and effective
string = input()
match = input()
res = ""
for i in string:
if match in i:
res += i
num = (len(res)/len(string))*100
print(int(num))

Answer 15

can you put the coding for this question
You are making a program to analyze text.
Take the text as the first input and a letter as the second input, and output the frequency of that letter in the text as a whole percentage.

Sample Input:
hello
l

Sample Output:
40

The letter l appears 2 times in the text hello, which has 5 letters. So, the frequency would be (2/5)*100 = 40.

Answer 16

Prakhar, damn, mate, seeing the simple int function at the end of your option I feel so dumb after solving this with the math.trunc method 😅 Well done!

Answer 17

text = input()
letter = input()
analyzed = letter in text
letter_count = text.count(letter)
text_len = len(text)

if analyzed:
print(int((letter_count / text_len) * 100))

# my take..

Answer 18

As a function.

t = input()
l = input()

def frequency(txt,letter):
tlen = int(len(t))
lc = t.count(l)
freq = int((lc / tlen) * 100)

return freq

print(frequency(t,l))

Answer 19

Short and Good!

stri=input()
L= input()
print(int(stri.count(L)/len(stri)*100))

Answer 20

A little longer than other examples but it's works

text = input()
letter = input()
txtLen= len(text)
ltcount= 0
for i in text:
if i == letter:
ltcount+=1
frecuency = (ltcount / txtLen)*100
print(int(frecuency))