“Rock the Space”! (Logical operators)

Question

“Along with other physical health requirements, astronaut candidates must have perfect vision (100%) and their height must be between 62 and 75 inches. Write a program that accordingly takes the vision percentage and height (in inches) as an input and prints "passed" if given conditions are satisfied and "failed" if otherwise.”
https://code.sololearn.com/crpAiAUzk0oW/?ref=app

Answer 1

'if' statement with multiple conditions must be put as one parenthesis expression (eventually with nested parenthesis, and ! (not) operator is missused (a not equals b is not a!b, nor a!(==b), but !(a==b) or simpliest a!=b):

if (vision==100) && (height>=62) && (height<=75) {

and:

if (vision!100) || (height!>=62) || (height!<=75)) {

should be:

if (vision==100 && height>=62 && height<=75) {

and:

if (vision!=100 || height<62 || height>75) {

Answer 2

Tahiti🍷

Yes but there is not any syntax like that in any programming language.

You can write

vision != 100
vision < 62
vision > 75

"Is not greater than or equal to" means value should be less than defined value

"Is not less than or equal to" means value should be greater than defined value.

Answer 3

#include <iostream>
using namespace std;

int main() {

int vision;
cin >> vision;

int height;
cin >> height;
//your code goes here
if ((vision==100) && (height>=62) && (height<=75)){
cout << "passed";
}
else{
cout << "failed";
}

return 0;
}

Is this okay??

Answer 4

K.Suhanya

There is word "between" so there should not be >= in your logic.

Answer 5

Okay I Am AJ ! .I just edit else part in Tahiti🍷's coding.
Anyway thanks for your comment. 😊

Answer 6

if (vision==100) && (height>=62) && (height<=75) {

and:

if (vision!100) || (height!>=62) || (height!<=75)) {

should be:

if (vision==100 && height>=62 && height<=75) {

and:

if (vision!=100 || height<62 || height>75) {

Answer 7

Tahiti🍷
in C as in almost all languages comparison operators are ==, !=, <, >, <=, >=, but not !< nor !<= nor !> nor !>= ;)

Answer 8

#include <iostream>
using namespace std;

int main() {

int vision;
cin >> vision;

int height;
cin >> height;
//your code goes here
if ((vision==100) && (height>=62) && (height<=75)){
cout << "passed";
}
else{
cout << "failed";
}

return 0;
}

Good Luck

Answer 9

Tahiti🍷

What is vision !100 and what is this syntax !>= and !<=

You need to learn about Operators again.

Answer 10

also, you could simplify, by replacing the second 'if' statement by an 'else' related to the first 'if' statement...

Answer 11

Tahiti🍷

Program is simple. Read the sentence again.

1 - vision should be 100 %
2 - height must be between 62 and 75. It means height > 62 && height < 75

So condition should be like this

if (vision == 100 && height > 62 && height < 75)
cout << "passed";
else
cout << "failed";

Answer 12

and change parenthesis ^^

Answer 13

or 62.00001, or 74.99999

Answer 14

that's how problem is stated...
we often need to decide less or more arbitrarly bounds. In this case the exercise seems to expect bounds not included ;)

Answer 15

Calvin Sheen Thomas ,
Yes, this helps tremendously. Thank you! I think the more times I look over the code, the more it begins to “sink in.”

Answer 16

Try this!!!!

#include <iostream>
using namespace std;

int main() {

int vision;
cin >> vision;

int height;
cin >> height;

if(vision == 100 && height>=62 && height<=75)
cout<<"passed"<<endl;
else
cout<<"failed"<<endl;

return 0;
}

Answer 17

#include <iostream>
using namespace std;

int main() {

int vision;
cin >> vision;

int height;
cin >> height;
//your code goes here
if (vision == 100 && height >= 62 && height <= 75) {
cout << "passed" << endl;
}
else {
cout << "failed" << endl;
}

return 0;
}

Answer 18

#include <iostream>
using namespace std;

int main() {

int vision;
cin >> vision;

int height;
cin >> height;
//your code goes here
if(height>=62 && height<75)
cout<<"passed";
else
cout<<"failed";

return 0;
}

Answer 19

Try this:

#include <iostream>
using namespace std;

int main()
{
int vision;
cin>>vision;
int height;
cin>>height;
if (height>=62 && height<=75 && vision==100){
cout<<"passed"<<endl;
}
else {
cout<<"failed"<<endl;
}
return 0;
}

Answer 20

This is my code and it works somehow lol:

#include <iostream>
using namespace std;

int main() {

int vision;
cin >> vision;

int height;
cin >> height;
//your code goes here
if (vision == 100 && height >= 62 && height <= 75){
cout << "passed" << endl;
} else if (vision != 100 || height >= 62 || height <= 75){
cout << "failed" << endl;
}

return 0;