[SOLVED] Can someone show me how char works

Question

I'm trying to do the lessons 7.1 on Java called Computer Speak, where a user inputs a letter and I have to print it out as a number, but I don't understand how char works so my code won't work

import java.util.Scanner;

class Main
{
public static void main(String[] args)
{
Scanner read = new Scanner(System.in);
String[] char a =read.next().charAt(0);
int count=97;
for(int i=0;i!=25;i++)
{
if(char a[i]==a)
{
char.replace[i]==count;
}
System.out.println(char[i]);
count++;
}
//your code goes here

}

Answer 1

char[] a will declare character array , not single character and you cant assign single character by that way..
Just do
char a = read.next().charAt(0);
and
if(a='a'||'A') will assign 'a' in a. And it returns always true.
if you are trying about checking a have 'a' or 'A' then it must be like
if( a== 'a' || a== 'A' )

Edit: Serana Zentha after removing error in your above updated code ,it just prints a space if 'if clouse is true' otherwise nothing..

Answer 2

Character declaration is just like :
ex: char a='a';

so you just need
char ch=read.next().charAt(0);

This will read a word but take only a charecter at index 0. and assign it into charecter variable ch.
You have wrong syntax in if condition.

To print it as a number, print its ascii value by casting it to int type as System.out.println( (int)ch);

Answer 3

Post your updated code..

String[] char a =read.next().charAt(0);

if(char a[i]==a)

char.replace[i]==count;

These 3 lines have wrong syntaxes.. Not valid statements.
If you checking 'a' then it must be
if(a == 'a')
About 3rd => i dont understand what you tried there..

Answer 4

Jayakrishna🇮🇳 i keep getting no output, no matter how I try to print it or cast it. it won't let me cast it

Answer 5

Jayakrishna🇮🇳 im trying to print a letter as a number by casting but i have no idea what this lesson even wants me to do as it throws char in my fave despite the fact I have no idea what char even does

Answer 6

Jayakrishna🇮🇳 I tried doing something simple just to print char a but this wint print either, I have no idea what I'm doing

i dont know how my syntax is wrong because i don't use char to begin with, could you please explain why my syntax is wrong, I know it's wrong but I don't know why I don't use char at all

import java.util.Scanner;

class Main
{
public static void main(String[] args)
{
Scanner read = new Scanner(System.in);
char[] a = read.next().charAt(0);

for(int i=0;i!=25;i++)
{

if(a='a'||'A')
{
System.out.println(" ");
}

}

Answer 7

Jayakrishna🇮🇳 thank you ill let you know if it works

Answer 8

Jayakrishna🇮🇳 it worked thank you soooo much i was starting to lose my mind

Answer 9

//sample code for casting.., check this once if you need..

import java.util.Scanner;
public class Program
{
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
char ch=in.next().charAt(0);
System.out.print((int)ch);
}
}

//Edit: Serana Zentha you're welcome..