Average Words Length Python

Question

For Average Words Length challenge in Python the function split() always returns a class ‘str’ to me rather than a class ‘list’.
Anyone has seen same behavior?

Thanks

https://code.sololearn.com/ciImr1czh929/?ref=app

Answer 1

Sergiu Panaite not to worry. It happens. Happy coding.

Answer 2

Can you Pls post the code to understand it..?

Answer 3

Sergiu Panaite
You are using strip() function ,not split() function.

strip() returns a string with removing leading and trailing spaces.
split() returns a list with splitting into words..

Answer 4

Jayakrishna🇮🇳 ha ha yeah that would be it.

Answer 5

can’t belive I was that blind, I always had impression I was writing split but was actually using strip. I feel embarassed ☹️. Thanks guys

Answer 6

Sergiu Panaite not to worry..
👍👍

Answer 7

It should return a list of strings.

Answer 8

Are you calling split() with an argument of " "?

Answer 9

E.g. this simple program splits a sentence into a list of words:

https://code.sololearn.com/cCqt749d8X6O/?ref=app

Answer 10

Actually, I learnt from David Ashton and Louis that split() without arguments does a better job at separating out the strings

Answer 11

Thanks Sonic , your code returns a list indeed, mine still returns a string. I’ve added the code in my original description.

Answer 12

Sergiu Panaite can you share a link to your code?

Answer 13

a = input()
x=(len(a)-a.count(" ")-a.count(".")-a.count(",")-a.count("?"))/(a.count(" ")+1)
print(int(x)+(x>x//1))

#Hope this code is working fine; did it in a hurry, might have bugs.

Answer 14

Here is the code

text = input()
spl = text.split()
print(spl)
no_char = len(text)
no_elment=len(spl)

print (no_char)
print (no_elment)
print (20/3)

#print ("%.2f" % (no_char/no_elment)

print("%.2f" % round((no_char/no_elment), 2))

but the output is coming as 6.666666666666667 instead of 6.0

Answer 15

i use
text = input()

word = text.split()

only_alpha = text.replace(" ", "")

print(len(only_alpha) / len(word))