Can anyone explain how the value of p is 9

Question

https://code.sololearn.com/cefJ09zohypS/?ref=app

Answer 1

Keep in mind that all #define do is text replacement at preprocessing stage.

So at compile time

r+=FNC(++p,q++)

Will be converted to

r+= (++p>q++)?(++p*q++):(++p-q++)

And now I think it should be pretty clear why value of *p* got incremented twice.

Answer 2

I think it is because firstly you pass that ++p into FNC, so it was incremented to 8, then "++p" got moved into the FNC body, and incremented to 9

Answer 3

Arsenic is right . The macro you declared above will just copy paste replacing the parameters x, y with ++p and q++.