c++ countdown program

Question

Pls do solve and send anyone

Answer 1

vijayalakshmi T.G. check it
while(n>0){
if(n%5==0){
cout<<n<<endl<<"Beep"<<endl; /* it will first print the number(multiple of 5) then will print beep */
n--; /* decreasing by 1*/
}
else{
cout<<n<<endl; /* if not multiple of 5 then will print only that number*/
n--;
}
}

Answer 2

Code: (Works)

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;
while(n>=1)
{
if(n%5==0){
cout<<n <<"Beep"<<"\n";}
else{
cout<<n;
}
n--;
}

return 0;
}

Answer 3

int main() {
int n;
cin >> n;
while(n>=1)
{
if(n%5==0){
cout<<n <<"Beep"<<"\n";}
else{
cout<<n;
}
n--;
}

return 0;
}

Answer 4

While(n>=1)
{
if(n=n%5);
Cout <<"Beep";
n--;
}

Answer 5

= is an assignment operator use == instead of that

Answer 6

Ok thank you

Answer 7

These are some necessary changes that you should bring in your code

Answer 8

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;
while (n>=1){
if (n%5==0){
cout << n << endl << "beep" << endl;}
else {
cout << n << endl;
}
n--;
}
return 0;
}

That works good, but i couldn't finish exercise because after number 1 programme still doing new blank line and app don't count it, anyone have some solution?

Answer 9

vijayalakshmi T.G. then show us your code .we can help you more accurately then .

Answer 10

Please post your try

Answer 11

// HI THERE!!

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;

while( n >= 1 ) {
if( n%5 == 0 ){
cout << n << '\n' << "Beep" << endl;
} else {
cout << n << '\n' << endl;
} n--;
}

return 0;
}

Answer 12

short and good!

#include <iostream>
using namespace std;
int main()
{int n;
cin >> n;
while(n>=1)
{if(n%5==0)
{cout<<n <<"Beep"<<"\n";}
else{cout<<n;}
n--;}
return 0;}

Answer 13

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;
while (n>0){
cout << n <<endl;
if (n%5==0){
cout << "Beep" << endl;
}
n--;
}
return 0;
}

Answer 14

#include <iostream>
using namespace std;

int main() {
int n;
cin >> n;

//your code goes here

for (int i=n; i>0; i--){

cout << i <<endl;

if (i%5==0){

cout<<"Beep"<<endl;

}

}

return 0;
}

Answer 15

It seems there is only one way and when I see it I understand it and it is easy but how (from so many functions and variations) do I ever know I have to use this method exactly? I tried to do n>0 first after if and then modulus of 5 in else but I wouldn't have guessed to start with modulus after if and then do the main part in else phase. I would be natural to me to make bigger part after if and smaller part after else but here it is other way around. My problem seems to reoccur that I know the methods but don't know which one to pick and how to twist them for that specific way that I just don't see.

Answer 16

Please solve it yourself.

https://www.sololearn.com/discuss/333866/?ref=app

Answer 17

I had written the code but i don't know where i did mistake