Java 18.2

Question

Show me solution to the problem please

Write a program that takes a number N as input and outputs numbers from N to 0, skipping multiples of 3.

Sample input
7

Result example
7
5
4
2
1
0

Answer 1

Put a condition in the loop that if (i%3==0). continue

Answer 2

they shouldn't be

Answer 3

import java.util.Scanner;

public class Main {

public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int N = read.nextInt();

for(int i = N; i >= 0; i--){
if(i%3==0)
continue;
System.out.println(i);

}
}}

//Check this

Answer 4

import java.util.Scanner;

public class Main {

public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int N = read.nextInt();

for(int i = N; i >= 0; i--){
if(i%3==0)
continue;
System.out.println(i);

} System.out.println("0");
}}

//Check this

Answer 5

can you explain what was wrong?

Answer 6

Do you get the answer? Do it passed all test cases?

Answer 7

Because in expected output 0 is present and remainder of any number with 0 is 0
So the if condition will continue that one

Answer 8

Do you get the answer? Do it passed all test cases?

Answer this question first

Answer 9

Run for loop and add if(n%3==0) that's it hope it helps you :)!!

Answer 10

Karthik Reddy Thotamgari But what about the 0 at the last?

Answer 11

Atul i forgot abt that thanks

Answer 12

import java.util.Scanner;

public class Main {

public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int number;
do {
//take input and output corresponding message
/*
1 => Language selection
2 => Customer support
3 => Check the balance
4 => Check loan balance
0 => Exit
*/
number=scanner.nextInt() ;

if(number==1)
{
System.out.println("Language selection");
}
else if(number==2)
{
System.out.println("Customer support");
}
else if(number==3)
{
System.out.println("Check the balance");
}
else if(number==4)
{
System.out.println("Check loan balance");
}
else
break;

}
while(number != 0);
System.out.println("Exit");
}
}

Answer 13

i've missed a case when i gave the response in 2021 and completely forgot abt that. just now saw this question again so answered, hope this helps :)
public class Main {
public static void main(String[] args) {
int n = 7;
call(n);
}
public static void call(int n){
if(n == 0){
System.out.println(n);
return;
}
if (n%3!=0){
System.out.println(n);
}
call(n-1);
}
}

Answer 14

Please post the question and answer

Answer 15

My code

import java.util.Scanner;

public class Main {

public static void main(String[] args) {
Scanner read = new Scanner(System.in);
int N = read.nextInt();

for(int i = N; i >= 0; i--){
System.out.println(i);

}
}

Answer 16

no digits divisible by 3

Answer 17

No in the loop you do divisibles of 3 will come

Answer 18

Wrong

Answer 19

Why println (“0”)? why did it prevent me from writing the program? nonsense