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Pointer concatenation using function
https://code.sololearn.com/ca3A24A4a3A1 Am I doing this right? from the output why G is showing like double times after the function being called?
11 Respostas
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So in the end, the value of `ss` should be "ZZZZZZZZZZABCDEFG" right?
You can do this easily using the function strncpy() from the <string.h> header.
https://code.sololearn.com/cdk0zB5E4l7p/?ref=app
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@Ipang
int m=len(ss)+len(s)+1
then char ss[m]
like this?
@XXX I have to do this according to the question otherwise I would have used string
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Martin,
Thanks for telling, but honestly, it's confusing that they wrote "first n bytes" when they didn't mean to limit the number of copied bytes, but rather just copy the entire string.
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The question is:
7.10
Write the following function that copies the first n bytes beginning with *s2 into the bytes
beginning at the location of the first occurrence of the null characterâ\0â after *s1, where
n is the number of bytes that s2 has to be incremented before it points to the null character
'\0':
void cat(char* s1,const char* s2)
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Your code appears to be changing contents of variable <s> accidentally.
I don't see any value of <n> in the code either. Shouldn't <n> be used to limit number of bytes copied over?
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@Ipang what do you mean by<n>?
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The task Description said:
"function that copies first n bytes ..."
That is what I mean by <n>. I thought your code was supposed to read a value of <n> to limit number of bytes to be copied.
Anyways, I've found the problem, you need to specify the size of variable <ss> to be at least (length-of-<ss>) + (length-of-<s>) + 1 for string terminator (null).
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Ramisa,
It depends,
If you were allowed to statically specify size of <ss> directly, then just do like that `char ss[30]`
But if you're supposed to specify size of <ss> dynamically, then you'd take the `malloc()` and `free()` approach (C way), or `new` and `delete` approach (C++ way).
The task didn't clearly specify whether <ss> was to be a static or dynamic char array, so I'm not too sure.
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Thank you
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thank you @Martin
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@Martin Thank you so much for elaborating