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How is this working, I mean how is python executing
a = [0,1,2,3] for a[-1] in a: print(a[-1]) https://code.sololearn.com/cs2mWY3hjmOs/?ref=app
9 Respostas
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https://code.sololearn.com/c2kNMIGR1HCC/?ref=app
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The for loop works like this:
for A in B:
-> Get the elements from B one at a time and assign that value to A. A is a[-1] in your code, so the value gets assigned to the last element of a.
Change the output to this:
print(a)
Then you can see the whole list in each iteration and see that only the last item changes.
In the last step a[-1] is 2 from the previous step and gets assigned to itself, so output is 2 again
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KishanBGajera take this modification of your code, it prints the complete list in the loop and the list is longer:
a = [0,1,2,3,4,5]
for a[-1] in a:
print(a)
Output is
[0,1,2,3,4,0]
[0,1,2,3,4,1]
[0,1,2,3,4,2]
[0,1,2,3,4,3]
[0,1,2,3,4,4]
[0,1,2,3,4,4]
As you can see only the last element (a[-1]) changes. It is set by the loop.
Read the loop like this: set a[-1] to each of the elements in a (one at a time) and run the code inside the loop
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Benjamin JĂŒrgens please elaborate I'm not getting it đ
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Benjamin JĂŒrgens thanks đ
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Sayedđ§đ©đ§đ© thanks đ
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It is a slicing
Last element (a[-1]) because you have given in the range
And your print a[-1] that is 2 and it will be assigned to itself so output is showing:-
0
1
2
2
Try-
a = [0,1,2,3]
for a[-1] in a:
print(a[-1], end="")
0
a = [0,1,2,3]
for i in a:
pass
print(i)
# everytime loop runs i is assigned corresponding value of list a from 0 index to -1 index . so it's final value is 3
a = [0,1,2,3]
for a[-1] in a:
print(a[-1])
# now consider same case with this one too .
# first iteration a[-1] = a[0] = 0
# 2nd iteration a[-1] = a[1] = 1
# 3rd iteration a[-1] = a[2] = 2
# 4th iteration a[-1] = a[3] which is a[-1] actually . in 3rd iteration a[-1] was assigned value 2 . so this time a[-1] = a[3] = a[-1] =2
#by Nicolaus Copernicus
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Thanks Nicolaus easily explained this problemđ