Average word length

Question

You are in a college level English class, your professor wants you to write an essay, but you need to find out the average length of all the words you use. It is up to you to figure out how long each word is and to average it out.

Task:
Takes in a string, figure out the average length of all the words and return a number representing the average length. Remove all punctuation. Round up to the nearest whole number.
here's my code isn't working import math
a = input()
b = a.replace(" ","")
c = a.split()
print(math.ceil(len(b)//len(c)))

either another coDe is.

a = input()
b = a.replace(" ","")
c = a.split()
print(round(len(b)//len(c)))

1st code is getting matched with question case. and 2nd matching with first 2 answer case but still not getting approved.
more cases are locked and I'm unable to check with that please help

Answer 1

At first you need to remove the punctuation. Using regex seems to be the easiest way.

After that you create a list using .split(" ")

And now you can count the length of each word using a loop, take the average (sum of length / number of words) and round it up with ceil()

Answer 2

First of all you are using floor division "//" Instead of simple division "/".

The question also asks for removing all punctuation .

In the following code i am not removing punctuations but checking for only alphabets and numbers .

import math

a = input()

b=list(filter(lambda x:x.isalnum(),a))

c = a.split()

print(math.ceil(len(b)/len(c)))

You don't need round function , questions clearly says " round up " which is what math.ceil do.

If you want to remove only punctuations instead of checking for alpha and num like i did , check the following question asked on stackoverflow.

https://stackoverflow.com/questions/265960/best-way-to-strip-punctuation-from-a-string

Answer 3

text = input()
text2 = text.replace(" ", "")
print (len(list(text2))/len(text.split()))

Answer 4

import math
t = input()
ch = "abcedfghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
C = 0
for char in t:
if char in ch:
c += 1
w = len(t.split(" "))
print(math.ceil(c/w))

Answer 5

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