Why it doesn't print all the dictionaries? ( SOLVED!!!)

Question

x = input ()
D = {}
for i in x:
D = { i : x. count(i) }

print(D)

I need to print exg: input = " awesome "
Output should {'a' :1, 'w':1, 'e':1, 's':1, 'o':1, 'm':1, 'e':2}

Answer 1

Because you recreate dictionary <D> to contain only a letter (represented by variable <i> in for-loop) and count of the letter in the given input string.

A dictionary can't have duplicate key, so you can't have 'e' : 1 and 'e' : 2 together in the dictionary.

Answer 2

SelvaKumar ,

here is a base code you can use and fill in the required code for the 2 cases:

str = input()
res = {}
for i in str:
if i in res:
# (fill in the code): if character already exists in dict: increment value by 1
else:
# (fill in the code): if character not exists, creare a new member in dict with character as key and 1 as value

print(res)

Answer 3

Your code shows only the last run. Last e is two times in the input.
Correct line 4 to

D[i] = x.count(i)