[Challenge 01] - Level: Begginer

Question

Make a program that identify if a phrase typed by the user is a palindrome or not.

Ex of a palindrome:
O LOBO AMA O BOLO
(It's in Portuguese. In English it means: the wolf loves the cake)

Source code (One of the possible solutions made in Python):
https://code.sololearn.com/c1NLCD1RYnNl/?ref=app

I hope you enjoy!

Answer 1

# shorter:

pal = True
inp = ''.join(input('Type a phrase: ').upper().split())
for i in range(len(inp)//2):
if inp[i] != inp[-i-1]:
pal = False
break
print(f'The phrase is {"" if pal else "not "}palindrome!')

Answer 2

Eren Ozer stop spamming ^^

Answer 3

I'm still learning python. I'm noob yet haha. Btw, thank you very much for your explanation!

Answer 4

visph sorry. I'm still learning about this app. I think now it's done.

Answer 5

str(input()) is pointless, as input still return a string

.strip() is pointless, as you join each .split() part with empty string

my solution also stop iteration as soon as a char is different ;)

Answer 6

# Another Solution

phrase = ''.join(str(input('Type a phrase: ')).strip().upper().split())
inverted = phrase[::-1]
print(f'The inverse of {phrase} is {inverted}.')
if phrase == inverted:
print('This phrase is palindrome!')
else:
print('This phrase is not palindrome!')

Answer 7

Mateus Ferraz less efficient: you iterate once to revert the string, and once more to compare both string ;P

also, that's the second time you set and immediatly remove the best answer mark from my answer ^^