Py args practice : can anyone helps correcting my code plz

Question

def my_min(x, *args):
if x < args:
return x
else：
for arg in args:
if arg < x:
yield arg

print(my_min(8, 13, 4, 42, 120, 7))

Answer 1

what's the purpose if your code?

if you expect to return the min value from the arguments passed, you can simply do:

def my_min(*args):
return min(args)

but why not using directly min function ;P

if you want to make a recursive function (only for *args practice, as you use min built-in inside):

def my_min(x, *args):
if len(args) == 0 or x < min(args):
return x
else:
return my_min(*args)

Answer 2

You're probably having issues because it's a generator function and your if statement isn't correct.
Your if statement is equivalent to the following with the current given arguments;
if 8 < [13, 4, 42, 120, 7]:

You can make the code work like;

def my_min(x, *args):
if x < min(args):
yield x
else:
for arg in args:
if arg < x:
yield arg

[print(x) for x in my_min(8, 13, 4, 42, 120, 7)]

Or

def my_min(x, *args):
if x < min(args):
return [x]

def nums_less_than_x():
for arg in args:
if arg < x:
yield arg

return nums_less_than_x()

[print(x) for x in my_min(2, 13, 4, 42, 120, 7)]

Answer 3

（from “Ipang”）

def my_min( x, *args ):
return min( x, min( args ) )