Guys I have tried to complete the python average word length program a lot of times but I can't get the result!

Question

Pls help me in getting the code ?

Answer 1

Ok... I didn't expect that at all!
You were a C programmer before, weren't you?

In python it's much simpler than that, given that the input consists of only alphabetic characters and single spaces, you can just

test = input()
words = len(test.split(" "))
spaces = words-1
print((len(test)-spaces)/words)

Answer 2

The easiest language is harder to learn than the language u already learned.
Coding python while thinking C..🥺🥺🥺.

Answer 3

Runtime Terror Have you ever heard of code golf? Might be something for you:
https://en.m.wikipedia.org/wiki/Code_golf

Answer 4

https://code.sololearn.com/c1E7k4MWw1r7/?ref=app

Answer 5

You can copy-paste it here or save it in code playground

Answer 6

Hemalatha.M, this may shock you... That is the complete code...

Answer 7

~LoneWolf yes Python it's not only easier, it's a completely different way of thinking

Answer 8

Runtime Terror Is that an attempt to present the most unreadable and least useful correct answer?

Answer 9

First, you have to split the input string using space as separator, and get the count of number of words using len() method .ie;

text = input()
words = text.split(" ")
words_count = len(words)

Then, iterate over the string to count the number of characters (Excluding spaces)
You can use a condition like this:

count = 0

for i in text:
if not i == " ":
count += 1

Then now you can divide the word count with the number of characters and print the output

I hope this helps :-)

Answer 10

Show your code

Answer 11

Calvin Thomas I'll give you a better one-liner

Also, @ everyone, the problem consists of space separated words, so don't check for characters that are not there in the first place
Also, it wants the mean, not the ceil nor the floor of it

( lambda x: print(len("".join(x))/len(x)) )(input().split(" "))

Answer 12

Can you show us one of your attempts?

Answer 13

Yes but how?

Answer 14

import string
punc= string.punctuation

test= input()

phrase=" "
count_letter =0
count_word =0
for i in range(len(test)):
phrase +=str(test[i])
print("character: " + phrase[i] + " ~ ")
if phrase[i] == " ":
count_word +=1
print("Adding a Word")
elif phrase[i] != " " and (phrase[i] not in punc): # not counting spaces and punctuations
count_letter +=1
print("Adding a Letter")
print(round(((count_letter)//count_word)+1))

Answer 15

Yes

Answer 16

Thank you guys

Answer 17

Runtime Terror I do like one-liners... But that is unreadable

Answer 18

Here's a one-liner possibility without any external modules:

(lambda x: print(int(k:=len(x.replace(" ",""))/(x.count(" ")+1))+(k>k//1)))("".join(x for x in input() if x not in ".,!?"))

# Hope this helps

Answer 19

Angelo Yours doesn't seem to work.

Answer 20

Calvin Thomas what input have you tested?