explain please

Question

There is such a task
We need to calculate the area of the rectangle.
Complete and call the function to output the area of the rectangle, taking 2 arguments as length and width. If sides are equal, the function should also show "Square" as the second output.

my code:

length = int(input())
width = int(input())
def area(length, width):
#your code
if length*width:
print (length*width)
elif length==width:
print(Square)
area(length, width)

why doesn't it output (square)?
displays everything except (square)

Answer 1

Hi!
In python, if statement evaluates true anything except empty string and 0 value.
That's why output is always length *width for any integers when length!=0 and
width!=0.
So, if statement should be like this
if length != width:

Second thing is that strings must be quoted with single or double quotes to declare as a variable.
print("Square")

Answer 2

Square should be in quotes likes "Square", also the if statement will work no matter what, so the elif statement won't work and won't print "Square"

Answer 3

Please tag the question properly

https://code.sololearn.com/W3uiji9X28C1/?ref=app

Answer 4

length = int(input())
width = int(input())
def area(length, width):
#your code
if length!=width:
print (length*width)
else:
print(f"{length*width}\nSquare")
area(length, width)

Answer 5

length = int(input())
width = int(input())
def area(length, width):
answer = length * width
if length != width:
print (f"Rectangle: {answer}")
elif length == width:
print(f"Square: {answer}")
area(length, width)