Python Core - 42.2 Practice (Exception Handling)

Question

Hey guys,

Can someone explain to me what's wrong with this code:

pin = int(input())
try:
print("PIN code is created")

except ValueError:
print("Please enter a number")

The error is defined in the exception, however it doesn't seem to be catching it, despite showing that the error is indeed occurring, as shown below.

" Traceback (most recent call last):
File "/usercode/file0.py", line 1, in <module>
pin = int(input())
ValueError: invalid literal for int() with base 10: 'hh88' "

As far as I can tell that should be all that's required, but I'm a noob and am probably missing something pretty obvious. Thanks!

Answer 1

try:
pin = int(input())
# PIN created
except ValueError:
# Please enter a number

The exception is uncaught because the conversion to int is performed outside the try...except block.

Answer 2

As Ipang pointed out the conversion has to be placed in the try block. As a rule everything that might throw an error should be put in a try block.

Answer 3

Well now, that was a bit of a dirty trick, they defined the pin variable outside of the try.. except block in the first place:

pin = input()
try:
#your code goes here

except ValueError:
#and here

Lesson learned, don't trust the default code haha. Thank you!

Answer 4

They put the input there, but not the conversion. But yes, it's a bit unfortunate since most people convert the input immediately.

Answer 5

pin = input()

try:
int(pin)
print("PIN code is created")
except :
print("please enter the number")

Guys real code is this👆

Answer 6

I had a similar problem, thank you guys for sharing your knowledge with us <3