Else Statment

Question

The code works as it is.
However, I thought the first "else" statement in the code should be indented by a tab. But then the code throws an error. Can you write the reason for this?

def is_prime(num):
if num > 1:
for i in range(2, int(num/2)+1):
if (num % i) == 0:
return False
break
else:
return True
else:
return False

for i in range(1, 20):
if is_prime(i + 1):
print(i + 1, end=" ")

Answer 1

Hi Bekir!
That's because it's a for-else statement not if-else.
It means the else clause belongs to the for loop, not the if statement. That's why the else part doesn't match with if block.
You can refer this article to understand how this statement works
https://www.pythontutorial.net/JUMP_LINK__&&__python__&&__JUMP_LINK-basics/python-for-else/

Answer 2

my question was about the else state

Answer 3

Thanks for answer Python Learner.

Answer 4

One question
return False
break
Will code reach "break" statement?

Answer 5

I think yes. if the "if" condition was false then the break command would not be reached. Return false only returend value. As far as I know it should be like this