Why !< or !> not works, where != works?

Question

You can say. Use >= and <= instead of !< and !> . but I'm not satisfied with this logic. what is the actual reason of giving error? why js developers not implementing this comparison operator?

Answer 1

KAZI MD SHAKIB HASSAN

because that's not valid operator.

not only js even any language doesn't have these operators

Answer 2

It is not valid in JavaScript. but it's validated in mathematics. we solve a lot problem in mathematics with this !< and !> operator. didn't we?

Answer 3

Because not less(!<) or no more(!>) equals less(<=)(<) and more(>=)(>)
Not equals(!=) It's easy not to repeat it differently

Answer 4

Because !< means >= and !> means <= , so there is no need for these oprators hense they are just bunch of code smells

Answer 5

I'm guessing the idea of <= and >= (and many more) implementation is based on syntactic inheritance, and it's not a bad idea.

After all, learners of a language will find the learning curve to be lessen when languages share things in common, such as these operator symbols.

A language inheriting things from its predecessors *might* gain more learners opposed to one that iplements its own unique syntax due to uniformity.

Just saying 👌

Answer 6

First I suggest to add [js] tag

These operators are not defined in js, and unfortunately js doesn't support operator overload (although there are some libraries to allow that ) due to ecma specifications.

Many other languages allows it natively, for example Haskell is one of the most famous for such thing.. e.g.

(!<) :: Ord t => t -> t -> Bool
a !< b = a >= b

0 !> 0 -> True
0 !< 0 -> True

It says : operator !< takes 2 comparable(Ord) variables of same type(t) and return Bool