0.01 is not callable

Question

# your code goes here
aux = 0
day = 30
mon = 0
while day < aux:
mon = mon + ( 0.01(2**aux))
aux =+ 1
print(mon)

In line 6 I have a problem , how could I solve?

Answer 1

Without the "*" python assumes you're trying to call a function called "0.01()". That's why the error message says "0.01 is not callable".

Answer 2

What are you trying to do? What is the expected output?

Answer 3

In everyday maths we often abbreviate "x * y" to "xy". In Python you can't do that; you always have to use "*".

Answer 4

Thanks, I forgot the "*" 😅

Answer 5

Since day = 30
and aux = 0
day < aux is False.
Therefore the loop will not be executed and the output is 0.

Answer 6

I'm solving the problem of one excercise that I have to do 0.01(2**n) and when I'm trying to run, show 0.01 is not callable

Answer 7

There is an operator missing between
0.01
and
(2**aux).
Most likely what you want is
0.01 * (2**aux)