How to provide default value for *args and **kwargs? (Python)

Answer 1

def f(*li,**di):
li = li or [1,2]
di = di or {"a":5,"b":6}

Answer 2

There isn't a default value, can you try explaining what you mean?

Answer 3

*args is for an iterable and *kwargs is for a dictionary

Answer 4

No, just add the defaults in before hand. The point of *args and *kwargs is to handle a changable amount of values. If you have set values it defeats the purpose.

Answer 5

I Think You Mean To Say Values.....
Values Are Used As:

def function(arg1, arg2, arg3):
# Code...

This Function Will Only Allow 3 Arguments Not More Than That Nor Less Than That...

Answer 6

Slick Like this..
def my_func(y=7, *args, **kwargs):
print(y)

my_func () # 7
my_func (10) # 10

#But how to do same with *args and **args?

Answer 7

Arsalan interesting!

Answer 8

Shubham Bhatia ,
The Answer You POSTED Is Actually A Python Program...
C Doesn't Use def To Create A Function!

Answer 9

Slick Yes but can't I provide it a default iterable for *args and default keywords for **kwargs same way I did with formal parameter?

Answer 10

Slick Okay Thank you!

Answer 11

def function(arg1, arg2, arg3) :
#Python Coding
#AngularJS developer.

This is C language Program. 💯