+ 1

My SQL practice 18

Please help me to solve this solution in SQL Last i tried: SELECT* From Apartments; SELECT AVG(price) FROM Apartments WHERE Price > 800;

19th Oct 2021, 4:00 PM
Muhamad Wildan Hermawan
Muhamad Wildan Hermawan - avatar
2 Respostas
+ 4
SELECT* FROM Apartments ( FROM upper case letters) and I remember : status = 'Not rented' should be used.
19th Oct 2021, 4:27 PM
**🇦🇪|🇦🇪**
**🇦🇪|🇦🇪** - avatar
+ 2
Thanks
19th Oct 2021, 4:32 PM
Muhamad Wildan Hermawan
Muhamad Wildan Hermawan - avatar