Why does this loop execute infintely

Question

#include <iostream>
// #include <algorithm>
#include <cstring>
#include <string_view>
#include <stdio.h>

using namespace std;

int main()
{
char selection; // grade entered by user
cout << " Enter selection" << endl;
selection = std::getchar();

while ((selection != 'X')){

switch ( selection ) // switch statement nested in while
{
case 'A':case 'a':// grade was uppercase A

cout<< "Ok" <<endl; break;

case 'B': case 'b':
cout<< "Ok" <<endl;

break;
case 'C':case 'c':

cout<< "ok" <<endl;

break; // exit switch

case 'D':case 'd': // grade was uppercase D
// or lowercase d

cout<< "bad" <<endl;

break; // exit switch

case 'F': case 'f':// grade was uppercase F
// or lowercase f

cout<< "bad" <<endl;

break; // exit switch

default:
cout << " Exit the program" << endl;
}

}
return 0;
}

Answer 1

If input is not X it will run infinitely cause you haven't put any exit condition nor more input option after the switch statement.

Put the input option just before the while loop end. In this case when you enter X, loop will break.

Answer 2

Reynolds Onyango Please provide the link to the code so that I can run and modify.

Answer 3

Ok when i do that it works but still one problem it displays the default option too
" Exit the program" even when a,b,c,d,f options are entered

Answer 4

x