Java try and catch - error

Question

import java.util.Scanner;

public class Main {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
int p = 0;

while (true) {
try {
System.out.print("Enter num: ");
p = input.nextInt();
} catch (Exception e) {
System.out.println("Error");
}
}
}
}

Why does when catch block gets infinite loop when its triggered?
I am pretty sure in python this ganna work because this is how i make error handling. Thankssssss

Answer 1

I don't see any `break` statement, is that the complete code? I think loops do not stop unless its exit condition was satisfied, or a `break` statement was issued (same goes for Python).

Answer 2

by catch, code normally continue after catch block
if you want read numbers till user sends something other, do

try {
while (true) {
System.out.print("Enter num: ");
p = input.nextInt();
}
} catch (Exception e) {
System.out.println("Error");
}

Answer 3

Ipang yeh i forgot to put but still looping the error.

Answer 4

Add the break statment after the System.out.println("Error")
So, control can move out from the loop.

Code:-
https://code.sololearn.com/cm5QEAEmXXjB/?ref=app