How to remove multiple elements with remove function?

Question

Remove maxs and mins & print the rest. Is there a way without using a & b and without repeating the same structure twice?
data = [1, 5, 7, 0.4, 0.4, 9, 9]
a = min(data)
while a in data:
data.remove(a)
b = max(data)
while b in data:
data.remove(b)
print(data)
#so...
while min(data) in data:
data.remove(min(data))
#doesn't work, which I expected

while min(data) in data:
data.remove(min(data))
break
#only removes the first of duplicates

a = min(data)
while a in data:
data.remove(a)
#works, but could you do it just with functions? Something like: remove the minimum, also until there is a minimum equal to this minimium, remove it, then stop searching for the new minimum

2nd Q: Can you remove different elements using one remove function (remove.data(1,5) or remove.data[1,5] didn't work, I guess the remove function is not meant for that (I'm not yet familiar with del function). Before moving on through lessons I just want to clear some things up)).

Answer 1

No worries buddy.
I misunderstood, thanks for feedback.

kudos to Slick

Answer 2

Jona Žonta

data = [1, 5, 7, 0.4, 0.4, 9, 9]

data.remove(min(data))
data.remove(max(data))

print(data)

Answer 3

Cool, that code should work. And yeah, make that code into a function with a integer list parameter. Then you can supply any list of numbers.

Thats what you do if you wanna use a peice of code multiple times. You make a function out of it, generalize the code, and use it wherever needed

Edit: and oh yeah Jona Žonta , i only used ''.join() because i was working with a string and .join() makes output look better. Not really a use with a list of numbers

Answer 4

https://code.sololearn.com/c1JqZc2wYM1B/?ref=app

Answer 5

Slick #Thanks, from your code I figured this works:
for i in range (data.count(min(data))):
data.remove(min(data))
for i in range (data.count(max(data))):
data.remove(max(data))
print(data)
#Is there a way to join this two structures into one? To be honest, I didn't understand why print(''.join(sent)). Should I necessarily add something like "char" (or "a" in the example above) into code?

Answer 6

Rik Wittkopp This gives [1, 5, 7, 0.4, 9], but I wanted [1, 5, 7].