Why am I getting no output?

Question

#include <iostream>

using namespace std;

class Car{

private:
int horsepowers;

public:

void setHorsepowers(int x) {
x = horsepowers;
if(horsepowers>800){

cout<<"Too much"<<endl;
}
}

int getHorsepowers() {
return horsepowers;
}

};

int main() {

int horsepowers;
cin >> horsepowers;

Car car;

car.setHorsepowers(horsepowers);

cout << car.getHorsepowers();

return 0;
}

Answer 1

Yes, that's right. You are calling the setter function with the VALUE in the x variable. And then this VALUE will be stored in horsepowers:

Variable <- Value
horsepowers = x

Answer 2

😮 Hmm, that's lesson one for variables.
This is a normal value assigment to a variable. This works only in one direction:

Variable <- new value

If both directions should be possible, how do the compiler should know, what direction do you want in this case?

Maybe you can look at it like this:
FIRST open a container,
THEN put in the items.

Answer 3

void setHorsepowers(int x) {
horsepowers = x;

Answer 4

Use:
horsepowers = x;
instead of
x = horsepowers;

void setHorsepowers(int x) {
horsepowers = x;
if(horsepowers>800){

Answer 5

SoloProg Coding Cat mind telling the difference between horsepowers = x and x = horsepowers?
Really curious on how the compiler understands one and not the other.

Answer 6

So in this case Variable is horsepowers and the parameter is X which is going to be the argument when called later by the function, am I right?
I was first confused because both aren't numbers,hence both are variables. Guess I was wrong there.