Why does this code returns 2?

Question

def func():
try:
return 1
finally:
return 2

k=func()
print(k)

there are supposed to be no error in try section, so if it returns anything it should be 1 and 2.
or does 2 overwrites the return of 1?

Answer 1

See this answer to a similar question on StackOverflow
https://stackoverflow.com/a/19805746

Answer 2

The finally block is always executed. And a function can only return one object.